My friend said that buying more lotto tickets doesn't improve your odds of winning.
you buy one ticket and it's 1:1million chance to win ok... if you buy 5 tickets, it is no longer 1:1million, cuz u added 5 tickets to the total equation...so you gain no advantages in odds by buying more than one tickett
Is he trolling me
It actually decreases your odds, if you buy more tickets
Buy one ticket, let's say that your chances of winning is 1/1 000 000, which is 1 x 10^-6 , but if you buy FIVE tickets, then your odds of winning is 1/1 000 005 which is about 9.99995 x 10^-7, which is slightly lower than your initial odds.
So therefore, buying 5 tickets slightly decreases your odds of winning, only very slightly though almost negligible
Anyway, I'm pretty sure for each ticket you buy, you find your probability by summing each individual probability and subtracting p1*p2. If you buy more tickets There's a union formula for it I believe, S1-S2+S3...+(-1)^n*Sn where each Sn represents the sum of the intersection of n sets for each possibly combination.
I'm actually thinking about it more and it's beginning to make less sense to use that approach, since the probability that two lottery tickets winning is 0? And I think this would be what the intersection of two sets is claiming?
Maybe like this:
Imagine a smaller lottery where a number is picked from 0 to 9. You pick a number, 1. Your odds are 1/10. Now let's say you pick another number, 2. Your odds are now clearly 2/10, or P(1)+P(2)-P(1 and 2) (clearly 0).
Let's say it was a different type of lottery, say a scratch off ticket. Each ticket has a 20% chance of winning. Odds of ticket 1 winning (specifically), .2. Odds of both tickets winning, 1/5*1/5=1/25=.04=4%. This can be seen more clearly when you write out all possible results by assuming there are 5 outcomes for each ticket, 4 of which result in failure. Now, the odds that either ticket 1 or ticket 2 will win are calculated via the union of the two, P(1)+P(2)-P(1 and 2). When you add more tickets, in order to count the odds of at least one ticket winning, formula in:
must be used.
behold, /sci/, as I unleash these dubs!
ill take my novel prize now
actually the possible events aren't just WIN and LOSE, because in LOSE, you have like millions of different ways you could lose, each which has it's own probability
trust me, i have pondered long and hard about this, I also used to think, why isn't the probability of anything happening half and half (half - it happens, half - it doesn't happen)? I mean it either Happens or it doesn't happen, so wouldn't the probability of everything be 1/2?
Then I came to the conclusion, that while those are two events, there can be several ways something doesn't happen, and several ways something does happen, hence the "The probability of everything happening is 1/2" isn't true
also check em
Do you want to know why it's SPECTACULAR?
there are 10 DUBS post, in this one thread, yet there are only 44 posts, so really, there should only be 4 posts that are doubles, BUT THERE ARE TEN!
yes, this is why it is spectacular
Greetings. My name is Patrick Bateman™, and I have contacted you for important matters.
I have taken notice to your post It is of high quality™, but it's not the contents of the post that I'm interested by, it's the post-number.
Your post-number is unlike any other that I've ever seen. It is unique, as no other will ever obtain your distinct strand of numbers, but that is not the only unique thing about it.
Look at the numbers at the very end. Take a close look at them, and you might even realize it, too. Your post-number has ended in repeating digits, that is why I am contacting you.
Doubles threads on /sci/? It's really the end, isn't it? It's been fun, at least.
>There are 22 posters in this thread.
>my face when
I love this.
I seriously do, this is the greatest thread ever
[s4s] is actually amazing, I finally found where i can go on a sad night, when I need some KEKs
/sci/ is my board for intellectual discussions
[s4s] is my board for KEKs
In order to calculate the probability, you need to know if the lottery allows multiple tickets with the same number. (If you can choose your number, then it automatically does.)
Also, if the lottery allows a number that no one picked to be the winner, then the odds would change.
Second ticket doubles your odds, third ticket increases it by 50%, fourth ticket by 33%, etc.
So each ticket you buy is less of a bargain for your money than the last. That's why I buy no more than 5.
Whenever you are buying a lottery ticket, what you are paying is not its "price" but the difference between the price and the expected value of the lottery. This is a positive amount.
Every time you buy a ticket, if you are risk neutral, you lose that amount.
Since you are not risk neutral (otherwise you wouldn't buy the ticket in the first place), but you are risk lover, go and buy as many as you -literally- want.
There are no arbitrage possibilities in lotteries, i.e. probabilities do not change EVER. So it is all a matter of how much you want to spend.
Correct me if I'm wrong, but in lotto it doesn't matter how many other tickets there are, what matters is that you guess the random sequence of numbers. So even if youre the only person playing, your odds are still terrible. It increases if you guess several numbers at the same time, if you're rich enough you could guess all numbers at the same time, but then you wouldn't need to play lotto
All the tickets are checked simultaneously. If you picked different numbers for each ticket (and if you didn't then you deserve the "idiot tax" anyway) then the odds do increase in your favor.
Are you retarded or is this an epic ruse?
He'd still have bettered his chances at winning by a factor of five regardless of how many players there are in total (meaning even if every single other ticket was owned by just one other player it would still make no difference).
What OP posted:
>My friend said that buying more lotto tickets doesn't improve your odds of winning.
What actually happened:
>My friend saw me buying multiple lotto tickets with my same lucky number, and pointed out that it doesn't improve my odds of winning.
He's right if you assume that every ticket you buy I is added to the total pool, which as far as I know isn't the case since tickets are pre printed and their total amount is constant.
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