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Help me figure this out
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Using the numbers 6300, 450, 3150, and 1350 make the number 26,850 using 9 with repeats allowed
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>>7589518
>using 9 with repeats allowed
wat?
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make 26,850 by adding 9 of the possible numbers allowing for repeats
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not possible, you sure you got the correct numbers?
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>>7589518
impossible
here are all possible combinations with sum of them included,
pastebin com/cu3BHRYx
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>>7589518
If my linear algebra is okay then:
we got these equations:
6300x + 450y + 3150z + 1350a = 26850
x + y + z + a = 9

Gauss reduction gives that z and a are free variables and
y = 5.10 - 0.54z - 0.85a
x = 3.9 - 0.46z - 0.15z

The decimals here are all rounded, they gave long streams of decimals in my calculator.

if we take z = 1 and a = 1 then
x = 3.29 and y = 3.71
x + y + z + a = 9 indeed but the problem is decimals
In this problem only whole numbers make sense
and only positive numbers make sense

I don't know which of the infinite combinations of Zs and As will give a whole number answer but what is true is that both Z and A can be any positive whole number in the range 1 - 4
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make 26,850 by adding 9 of the possible numbers allowing for repeats
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Try using 4800 as an extra unit
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I've found only one combination so far 4800plus (4)3150 plus 6300 (2)1350 450
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>>7589768
6300 + 4800 + 3150 + 3150 + 3150 + 3150 + 1350 + 1350 + 450
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>>7589768
also (3)6300 + 4800 + 1350 + (4)450
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So is that it only two combinations?
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>>7589805
that's two more than you could figure on your own faggot
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>>7589816
Actually I was the one that posted the first combination I just have no idea how to find any others since there are other requirements like 3150 and 4800 have to be used at least once
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>>7589754
26850 (6300, 6300, 6300, 450, 450, 450, 450, 1350, 4800)
26850 (6300, 450, 3150, 3150, 3150, 3150, 1350, 1350, 4800)
26850 (450, 450, 450, 3150, 3150, 4800, 4800, 4800, 4800)
26850 (450, 3150, 1350, 1350, 1350, 4800, 4800, 4800, 4800)