No, it is an extension of multiplication, in the same way subtraction is the addition of negative numbers (addition of inverse quantities), division is multiplication by inverse quantities.
Addition, and multiplication have definitions that go beyond numbers. For example, vectors defined by a radius and angle, there is an addition and multiplication that follows the same rules as the addition and multiplication of numbers but gives different results.
Addition and multiplication are operations on objects that follow specific rules, and while they may simplifiy to arithmetic when dealing with numbers that is not true for all objects.
Since you're obviously mentally retarded I'll make this real easy for you to understand.
Let's take 20/5, which equals 4. This is the same as subtracting 4 from 20 five times.
20 -4 - 4 - 4 - 4 - 4 = 0
Same with 3/5
3 - 0.6 - 0.6 - 0.6 - 0.6 - 0.6 = 0
This doesn't mean 3/5 equals 0 as you erroneously stated, but rather that subtracting 0.6 from 3 five times equals 0. Now stop posting because you just got BTFO.
Take a class in abstract algebra, all of you, please.
Division (on real numbers) isn't really division at all as the real numbers are a field over only addition and multiplication. Divison can't be properly defined due to the presence of 0. Dividing by a is just a shorthand way of saying multiply by 1/a
algebraically, inversion is a group involutive automorphism.
Now assuming your group is abelian.
"division by a" could be defined as the composite morphism of multiplication by inverse of a.
>Division (on real numbers) isn't really division at all as the real numbers are a field over only addition and multiplication.
>Divison can't be properly defined due to the presence of 0.
It can, but it requires to use Projective line. Define inf = 1/0. Then 1/inf = 0, and for any a in R, a+inf = (a*0+1)/0=1/0=inf, as one would imagine.
>saying "division" instead of just multiplication by an inverse